How to add default values to input arguments in graphql

GraphqlGraphql Js

Graphql Problem Overview


I have this input type and I would like to add a default Value to one of the fields. I want to add 0 to the value field inside the ExampleInput.

type ExampleType {
  value: Int
  another: String
}

type Mutation {
  example(input: ExampleInput): ExampleType
}

input ExampleInput {
  value: Int
  another: String
}

Any ideas?

Graphql Solutions


Solution 1 - Graphql

It looks like the grammar allows default values on input object types, so you can declare

input ExampleInput {
  value: Int = 0
  another: String
  isAvailable: Boolean = false
}

The spec is clear that default values exist and explains how they get used (first bullet under "Input Coercion").

(Whether any specific tooling supports this is probably variable: graphql.org had an informal version of the IDL for quite a while before it was actually in the spec, and I have the impression some libraries haven't caught up to the released spec yet.)

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Content TypeOriginal AuthorOriginal Content on Stackoverflow
QuestionAdolfoView Question on Stackoverflow
Solution 1 - GraphqlDavid MazeView Answer on Stackoverflow