Inline conditions in Lua (a == b ? "yes" : "no")?

Is there anyway to use inline conditions in Lua?

Such as:

print("blah: " .. (a == true ? "blah" : "nahblah"))

Sure:

print("blah: " .. (a and "blah" or "nahblah"))

If the a and t or f doesn't work for you, you can always just create a function:

function ternary ( cond , T , F )
    if cond then return T else return F end
end

print("blah: " .. ternary(a == true ,"blah" ,"nahblah"))

of course, then you have the draw back that T and F are always evaluated.... to get around that you need to provide functions to your ternary function, and that can get unwieldy:

function ternary ( cond , T , F , ...)
    if cond then return T(...) else return F(...) end
end

print("blah: " .. ternary(a == true ,function() return "blah" end ,function() return "nahblah" end))

Although this question is fairly very old, I thought it would be fair to suggest another alternative that syntactically appears very similar to that of the ternary operator.

Add this:

function register(...)
    local args = {...}
    for i = 1, select('#', ...) do
        debug.setmetatable(args[i], {
            __call = function(condition, valueOnTrue, valueOnFalse)
                if condition then
                    return valueOnTrue
                else
                    return valueOnFalse
                end
            end
        })
    end
end

-- Register the required types (nil, boolean, number, string)
register(nil, true, 0, '')

And then use it like this:

print((true)  (false, true)) -- Prints 'false'
print((false) (false, true)) -- Prints 'true'
print((nil)   (true, false)) -- Prints 'false'
print((0)     (true, false)) -- Prints 'true'
print(('')    (true, false)) -- Prints 'true'

---

> Note: For tables, however, you cannot use them directly with the above method. This is because each and every table has it's own independent metatable and Lua does not allow you to modify all tables at once. > > In our case, an easy solution would be to convert the table into a boolean using the not not trick: > > lua > print((not not {}) (true, false)) -- Prints 'true' >

Have fun :D

local n = 12
do
    local x = (n>15)
            and print(">15")
            or n>13
            and print(">13")
            or n>5
            and print(">5")
end

You could just write the if statement in one line, it is no shorthand, inline or ternary operator stuff tho.

if (dummy == true) then
    print("dummy is true")
end

is equal too

if (dummy = true) then print("dummy is true") end

You can usually do:

condition and ifTrue or ifFalse

but this isn't necessarily the best way to do it. The major reason why is because if ifTrue is a falsy value (some of the time), ifFalse will evaluate even if condition is a truthy value. One way to do it simply without much extra work is:

(condition and {ifTrue} or {ifFalse})[1]

which has the advantage of not only being an expression and not being subject to the problem of ifTrue being falsy which means it can handle all cases, but also has the advantage of short-circuiting (not evaluating the other expression). No need for extra functions or messing with complex aspects of Lua.