Show a child form in the centre of Parent form in C#

I create a new form and call from the parent form as follows:

loginForm = new SubLogin();   
loginForm.Show();

I need to display the child form at the centre of the parent. So,in the child form load I do the foll:`

Point p = new Point(this.ParentForm.Width / 2 - this.Width / 2, this.ParentForm.Height / 2 - this.Height / 2);
this.Location = p;

But this is throwing error as parent form is null. I tried setting the Parent property as well, but didn't help. Any inputs on this?

Try:

loginForm.StartPosition = FormStartPosition.CenterParent;
loginForm.ShowDialog(this);

Of course the child for will now be a blocking form (dialog) of the parent window, if that isn't desired then just replace ShowDialog with Show..

loginForm.Show(this);

You will still need to specify the StartPosition though.

The setting of parent does not work for me unless I use form.ShowDialog();.

When using form.Show(); or form.Show(this); nothing worked until I used, this.CenterToParent();. I just put that in the Load method of the form. All is good.

Start position to the center of parent was set and does work when using the blocking showdialog.

There seems to be a confusion between "Parent" and "Owner". If you open a form as MDI-form, i.e. imbedded inside another form, then this surrounding form is the Parent. The form property StartPosition with the value FormStartPosition.CenterParent refers to this one. The parameter you may pass to the Show method is the Owner, not the Parent! This is why frm.StartPosition = FormStartPosition.CenterParent does not work as you may expect.

The following code placed in a form will center it with respect to its owner with some offset, if its StartPosition is set to Manual. The small offset opens the forms in a tiled manner. This is an advantage if the owner and the owned form have the same size or if you open several owned forms.

protected override void OnShown(EventArgs e)
{
    base.OnShown(e);
    if (Owner != null && StartPosition == FormStartPosition.Manual) {
        int offset = Owner.OwnedForms.Length * 38;  // approx. 10mm
        Point p = new Point(Owner.Left + Owner.Width / 2 - Width / 2 + offset, Owner.Top + Owner.Height / 2 - Height / 2 + offset);
        this.Location = p;
    }
}

Assuming your code is running inside your parent form, then something like this is probably what you're looking for:

loginForm = new SubLogin();
loginForm.StartPosition = FormStartPosition.CenterParent
loginForm.Show(this);

For the record, there's also a Form.CenterToParent() function, if you need to center it after creation for whatever reason too.

When launching a form inside an MDIForm form you will need to use .CenterScreen instead of .CenterParent.

FrmLogin f = new FrmLogin();
f.MdiParent = this;
f.StartPosition = FormStartPosition.CenterScreen;
f.Show();

childform = new Child();
childform.Show(this);

In event childform load

this.CenterToParent();

You need this:

Replace Me with this.parent, but you need to set parent before you show that form.

  Private Sub ÜberToolStripMenuItem_Click(ByVal sender As System.Object, ByVal e As System.EventArgs) Handles ÜberToolStripMenuItem.Click
        
        'About.StartPosition = FormStartPosition.Manual ' !!!!!
        About.Location = New Point(Me.Location.X + Me.Width / 2 - About.Width / 2, Me.Location.Y + Me.Height / 2 - About.Height / 2)
        About.Show()
    End Sub

When you want to use a non-blocking window (show() instead of showDialog()), this not work:

//not work with .Show(this) but only with .ShowDialog(this)
loginForm.StartPosition = FormStartPosition.CenterParent;
loginForm.Show(this);

In this case, you can use this code to center child form before display the form:

//this = the parent
frmDownloadPercent frm = new frmDownloadPercent();
frm.Show(this); //this = the parent form
//here the tips
frm.Top = this.Top + ((this.Height / 2) - (frm.Height / 2));
frm.Left = this.Left + ((this.Width / 2) - (frm.Width / 2));

It works in all cases, swap Form1 for your main form.

Popup popup = new Popup();
popup.StartPosition = System.Windows.Forms.FormStartPosition.Manual;
popup.Location = new System.Drawing.Point((Form1.ActiveForm.Location.X + Form1.ActiveForm.Width / 2) - (popup.Width / 2),(Form1.ActiveForm.Location.Y + Form1.ActiveForm.Height / 2) - (popup.Height / 2));
popup.Show(Form1.ActiveForm);

On the SubLogin Form I would expose a SetLocation method so that you can set it from your parent form:

public class SubLogin : Form
{
   public void SetLocation(Point p)
   {
      this.Location = p;
   }
} 

Then, from your main form:

loginForm = new SubLogin();   
Point p = //do math to get point
loginForm.SetLocation(p);
loginForm.Show();

If you want to calculate your own location, then first set StartPosition to FormStartPosition.Manual:

Form Child = new Form();
Child.StartPosition = FormStartPosition.Manual;
Child.Location = new Point(Location.X + (Width - Child.Width) / 2, Location.Y + (Height - Child.Height) / 2);
Child.Show(this);

Where this is the main/parent form, just like Location.X.

Default value for StartPosition is FormStartPosition.CenterParent and therefore it changes the child's location after showing.

Make a Windows Form , then put option for it : CenterParent then use this Code :

yourChildFormName x = new yourChildFormName();
x.ShowDialog();

You can set the StartPosition in the constructor of the child form so that all new instances of the form get centered to it's parent:

public MyForm()
{
	InitializeComponent();

	this.StartPosition = FormStartPosition.CenterParent;
}

Of course, you could also set the StartPosition property in the Designer properties for your child form. When you want to display the child form as a modal dialog, just set the window owner in the parameter for the ShowDialog method:

private void buttonShowMyForm_Click(object sender, EventArgs e)
{
    MyForm form = new MyForm();
    form.ShowDialog(this);
}

If any windows form(child form) is been opened from a new thread of Main window(parent form) then its not possible to hold the sub window to the center of main window hence we need to fix the position of the sub window manually by means of X and Y co-ordinates.

In the properties of Subwindow change the "StartPosition" to be "Manual"

#code in main window

private void SomeFunction()
{
    Thread m_Thread = new Thread(LoadingUIForm);
    m_Thread.Start();
    OtherParallelFunction();
    m_Thread.Abort();
}

private void LoadingUIForm()
{
    m_LoadingWindow = new LoadingForm(this);
    m_LoadingWindow.ShowDialog();
}

#code in subwindow for defining its own position by means of parent current position as well as size public LoadingForm(Control m_Parent) { InitializeComponent(); this.Location = new Point( m_Parent.Location.X+(m_Parent.Size.Width/2)-(this.Size.Width/2), m_Parent.Location.Y+(m_Parent.Size.Height/2)-(this.Size.Height/2) ); }

Here the co-ordinates of center of parent is calculated as well as the subwindow is kept exactly at the center of the parent by calculating its own center by (this.height/2) and (this.width/2) this function can be further taken for parent relocated events also.

As a sub form i think it's not gonna Start in the middle of the parent form until you Show it as a Dialog. .......... Form2.ShowDialog();

i was about to make About Form. and this is perfect that's i am searching for. and untill you close the About_form you cant Touch/click anythings of parents Form once you Click for About_Form (in my case) .Coz its Showing as Dialog

The parent probably isn't yet set when you are trying to access it.

Try this:

loginForm = new SubLogin();
loginForm.Show(this);
loginForm.CenterToParent()

If you have to center your childForm, from childForm then the code will be something like this. This code is in the childForm.cs

this.Show(parent as Form);    // I received the parent object as Object type
this.CenterToParent();

	protected override void OnLoad(EventArgs e) {
		base.OnLoad(e);

		CenterToParent();
	}

Why not use this?

LoginForm.WindowStartupLocation = Windows.WindowStartupLocation.CenterOwner 

(vb.net)